All about lambda functions in C++
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Lambda function is quite an intuitive & widely loved feature introduced in C++11. And, there are tons of articles & tutorials already available on the topic. But, there are very few or none of them touched upon things like IIFE, types of lambda and newer updates on lambda by subsequent standard releases. So, I got the opportunity to fill the blank. I will start this article with what is lambda function! And as we move along will show you how it works internally! & different variations of it. My focus here would be to give you a pragmatic overview. If you are in search of deep dive, I would suggest you read C++ Lambda Story by Bartłomiej Filipek.

Title of this article is a bit misleading. Because lambda doesn’t always synthesize to function pointer. It’s an expression (precisely unique closure). But I have kept it that way for simplicity. So from now on, I might use them interchangeably.

What is lambda function?

A lambda function is short snippets of code that

  • not worth naming(unnamed, anonymous, disposable, etc. whatever you can call it),
  • and also not reused.

In other words, it’s just syntactic sugar. lambda function syntax is defined as:

[ capture list ] (parameters) -> return-type  
    method definition
  • Usually, compiler evaluates a return type of a lambda function itself. So we don’t need to specify a trailing return type explicitly i.e. -> return-type.
  • But in some complex cases, the compiler unable to deduce the return type and we need to specify that.

Why Should We Use a Lambda Function?

C++ includes many useful generic functions like std::for_each, which can be handy. Unfortunately, they can also be quite cumbersome to use, particularly if the functor you would like to apply is unique to the particular function. Consider the following code for an example:

struct print {
	void operator()(int element) {
		cout << element << endl;

int main(void) {
	vector<int> v = {1, 2, 3, 4, 5};
	for_each(v.begin(), v.end(), print());
  • If you use print once, in that specific place, it seems overkill to be writing a whole class just to do something trivial and one-off.
  • However, for this kind of situation inline code would be more suitable & appropriate which can be achieved by lambda function as follows:
for_each(v.begin(), v.end(), [](int element) { cout << element << endl; });

How Does Lambda Functions Works Internally?

[&i] ( ) { cout << i; }

// is equivalent to

struct anonymous {
    int &m_i;
    anonymous(int &i) : m_i(i) {}
    inline auto operator()() const {
        cout << m_i;
  • The compiler generates unique closure as above for each lambda function. Finally, the secret revealed. Unique closure is nothing but a class(or struct depending upon compiler developer).
  • Capture list will become a constructor argument in closure, If you capture argument as value then corresponding type data member is created within the closure.
  • Moreover, you can declare variable/object in the lambda function argument, which will become an argument to call operator i.e. operator().

Benefits of Using a Lambda Function

  • Zero cost abstraction. Yes! you read it right. lambda doesn’t cost you performance & as fast as a normal function.
  • In addition, code becomes compact, structured & expressive.

Learning Lambda Expression Syntax

Capture by Reference/Value

int main() {
	int x = 100, y = 200;

	auto print = [&] { // Capturing everything by reference(not recommended though)
		cout << __PRETTY_FUNCTION__ << " : " << x << " , " << y << endl;

/* Output
main()::<lambda()> : 100 , 200
  • In the above example, I have mentioned & in capture list. which captures variable x & y as reference. Similarly, = denotes captured by value, which will create data member of the same type within the closure and copy assignment will take place.
  • In addition, the parameter list is optional, you can omit the empty parentheses if you do not pass arguments to the lambda expression.

Lambda Capture List

  • The following table shows different use cases for the same:
[ ] ( ) { }no captures
[=] ( ) { }captures everything by copy(not recommended)
[&] ( ) { }captures everything by reference(not recommended)
[x] ( ) { }captures x by copy
[&x] ( ) { }captures x by reference
[&, x] ( ) { }captures x by copy, everything else by reference
[=, &x] ( ) { }captures x by reference, everything else by copy

Passing Lambda as Parameter

template <typename Functor>
void f(Functor functor) {
	cout << __PRETTY_FUNCTION__ << endl;

/* Or alternatively you can use this
void f(function<int(int)> functor) {
    cout << __PRETTY_FUNCTION__ << endl;

int g() {
	static int i = 0;
	return i++;

int main() {
	auto lambda_func = [i = 0]() mutable { return i++; };
	f(lambda_func); // Pass lambda
	f(g);			// Pass function
/* Output
Function Type : void f(Functor) [with Functor = main()::<lambda(int)>]
Function Type : void f(Functor) [with Functor = int (*)(int)]
  • As you can see, you can also pass lambda function as an argument to other function just like a normal function.
  • So, if you see, here I have declared variable i in capture list which will become data member. As a result, every time you call lambda_func, it will be returned and incremented.

Capture Member Variable in Lambda or This Pointer

class Example {
	int m_var;
	Example() : m_var(10) {}
	void func() {
		[=]() { cout << m_var << endl; }(); // IIFE

int main() {
	Example e;
  • this pointer can also be captured using [this], [=] or [&]. In any of these cases, class data members(including private) can be accessed as you do in a normal method.
  • If you see the lambda expression line, I have used extra () at the end of the lambda function declaration which used to calls it right thereafter declaration. It is called IIFE (Immediately Invoked Function Expression).

Lambda Function Variations in Modern C++

Generic Lambda(C++14)

const auto l = [](auto a, auto b, auto c) {};

// is equivalent to

struct anonymous {
    template <class T0, class T1, class T2>
    auto operator()(T0 a, T1 b, T2 c) const {
  • Generic lambda introduced in C++14 which can captures parameters with auto specifier.

Variadic Generic Lambda(C++14)

template <typename... Args>
void print(Args &&... args) {
	(void(cout << forward<Args>(args) << endl), ...);

int main() {
	auto variadic_generic_lambda = [](auto &&... param) {

	variadic_generic_lambda(1, "lol", 1.1);
  • Lambda with variadic template(C++11) will be useful in many scenarios like debugging, repeated operation with different data input, etc.

Mutable Lambda Function(C++11)

  • Typically, a lambda’s function call operator is const-by-value which means lambda requires mutable  keyword if you are capturing anything by-value.
[]() mutable {}

// is equivalent to

struct anonymous {
    auto operator()() { // call operator
  • We have already seen an example of this above. I hope you noticed it.

Lambda as a Function Pointer(C++11)

auto funcPtr = +[] {};
static_assert(is_same<decltype(funcPtr), void (*)()>::value);
  • You can force the compiler to generate lambda as a function pointer rather than closure by adding + in front of it as above.

Higher-Order Returning Lambda Functions(C++11)

const auto less_than = [](auto x) {
	return [x](auto y) {
		return y < x;

int main() {
	auto less_than_five = less_than(5);
	cout << less_than_five(3) << endl;
	cout << less_than_five(10) << endl;
  • Going a bit further, lambda function can also return another lambda function. This will open the doors of endless possibility for customization, code expressiveness & compactibility(BTW, there is no word like this) of code.

constexpr Lambda Expression(C++17)

Since C++17, a lambda expression can be declared as constexpr.

constexpr auto sum = [](const auto &a, const auto &b) { return a + b; };
    is equivalent to

    constexpr struct anonymous
        template <class T1, class T2>
        constexpr auto operator()(T1 a, T2 b) const
            return a + b;
static_assert(sum(10, 10) == 20);
  • Even if you don’t specify constexpr , the function call operator will be  constexpr anyway, if it happens to satisfy all constexpr function requirements.

Template Lambda Expression(C++20)

  • As we saw above in generic lambda function, we can declare parameters as auto. That in turn templatized by compiler & deduce the appropriate template type. But there was no way to change this template parameter and use real C++ template arguments. For example:
template <typename T>
void f(vector<T>&	vec){
	//. . .
  • How do you write the lambda for the above function which takes std::vector of type T? This was the limitation till C++17, but with C++20 it is possible as below:
auto f = []<typename T>(vector<T>&  vec){
    // . . .

std::vector<int> v;
  • There are other small changes as well regarding the same that you can read here.

Parting Words

I hope you enjoyed this article. I have tried to cover most of the fundamentals around lambda function with a couple of unsophisticate & small examples. You should use lambda wherever it strikes in your mind considering code expressiveness & easy maintainability. For example, you can use it in custom deleters for smart pointers, to avoid code repetition & with most of the STL algorithms.

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Learn lambda function in C++ with example